Matematika Kelas 9 Halaman 30-32: Kunci Jawaban dan Cara Hitung Pembagian Perpangkatan

Soal nomor 2

a. (-y)5/(-y)2
= (-y)5-2=3
= y3

b. (1/t)7/(1/t)3
= (1/t)7-3=4
= 1/t7/1/t3
= 1/t7 . t3/1
= t3/t7
= t
= 1/t4

c. 3m7/m3
= 3m7-3=4
= 3m4

d. 42y8/12y5
= 42/12 . y8/y5
= (7/2)y3

e. ((1/t)7 : (1/t)3) x ((1/t)3 : (1/t)2)
= 1/t7/1/t3 x 1/t3/1/t2
= 1/t7/1/t2
= 1/t^7 . t2/1
= t2/t7
= t-5
= 1/t5

f. 3w4/w2 x 5w3
= 3w2 x 5w3
= 15 w5

Soal nomor 3

a. (0,24 x 0,22) : 0,25
= (0,2)4+2-5 = 1
= (0,2)1
= 1/5

b. (-5)5: (-5)2 x (-5)2
= (-5)5-2+2 = 1
= (-5)1
= -5

c. 12 + (47/46)
= 12 + 47-6 = 1
= 12 + 4
= 16

d. ((3 x 54)/53) – 15
= 3 x 5 – 15
= 15 - 15
= 0

e. (45 : 44) – (24 : 23) x 6
= 4 – 24/23 x 6
= 4 – 2 x 6
= -8

Soal Nomor 4

a. 1/2-5, 1/2-2 . 2-3, 1/(32)-1